Question

A rocket travels vertically at a speed of 1200 km/hr.

The rocket is tracked through a telescope by an observer located 11 km from the launching pad.

Find the rate at which the angle between the telescope and the ground is increasing 3 min after lift-off.

(Round your answer to two decimal places.)

Answer 1

my draw button is not working

Answer 2

Where to go from there?

Answer 3

\( \Large { \tan\theta = \frac{y}{11}\\ ~ \\
\\ \therefore implicit ~ derivative~ with~ respect ~ to ~ time \\
\sec^2 \theta \cdot \frac{d\theta}{dt} = \frac{1}{11} \cdot \frac{dy}{dt}

} \)

Answer 4

we want to find \( \Large \frac{d\theta}{dt} \) , when \( \Large \frac{dy}{dt}=1200 \) and
t = 3/60 hour

Answer 5

What is d theta/dt?