Question

Check simplification of trig

Answer 1

\[\frac{ \cos^2x }{ \cot^2x }\]

Answer 2

I put cot^2x as cos^2/sin^2

Answer 3

multiplied it out as (cos^2x)(sin^2x)/cos^2x)

ends up being just sin^2x?

Answer 4

@matt101

Answer 5

@mathmath333 @acxbox22

Answer 6

\(\large \color{black}{\begin{align} \dfrac{ \cos^2x }{ \cot^2x }=\sin^2x\hspace{.33em}\\~\\

\end{align}}\)

Answer 7

So I was right

Answer 8

yes

Answer 9

ty