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(x/100) + (y/66) = (3x+5y)/z. What is z?
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first i would multiply both sides by z*100*66, that will clear fractions
So I would just be left with the variables?
On the right side.
I would say multiply all sides by z to get \(\dfrac{x}{100}+\dfrac{y}{66} = \dfrac{3x+5y}{z}\) \(\dfrac{x}{100}z+\dfrac{y}{66}z = \dfrac{3x+5y}{z}z\) \(\dfrac{1}{100}xz+\dfrac{1}{66}yz = 3x+5y\)
Right?
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I'm a little confused..
Hm.
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