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Evaluate [3(5 + 6) + 2]÷7 A. 3 B. 5 C. 23/7
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PEMDAS
start with your inner parenthesis and work outward
PARENTHESES EXPONENT MULTIPLY DIVIDE ADD SUBTRACT so yeah do the parentheses first then do it in the order of PEMDAS
Do I start from the inner parenthesis?
yes then the brackets
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I got 15 :'(
i got 5 and a bunch of decimals
3[3(5+6)+2/7 3[3*11+2]/7 3[33+2]/7 3*35/7 105/7 15.
first P \(\huge\color{green}{{\rm P}}\)arentheses distribute (5+6) by 3
\(\color{blue}{\text{Originally Posted by}}\) @Surhur 3[3(5+6)+2/7 3[3*11+2]/7 3[33+2]/7 3*35/7 105/7 15. \(\color{blue}{\text{End of Quote}}\) how did you get 3 ??? front of [ ]
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|dw:1427078586431:dw| there isn't any 3
so 35/7 ?
|dw:1427078620992:dw|
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