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Mathematics 7 Online
OpenStudy (anonymous):

Evaluate [3(5 + 6) + 2]÷7 A. 3 B. 5 C. 23/7

OpenStudy (acxbox22):

PEMDAS

OpenStudy (triciaal):

start with your inner parenthesis and work outward

OpenStudy (acxbox22):

PARENTHESES EXPONENT MULTIPLY DIVIDE ADD SUBTRACT so yeah do the parentheses first then do it in the order of PEMDAS

OpenStudy (anonymous):

Do I start from the inner parenthesis?

OpenStudy (acxbox22):

yes then the brackets

OpenStudy (anonymous):

I got 15 :'(

OpenStudy (anonymous):

i got 5 and a bunch of decimals

OpenStudy (anonymous):

3[3(5+6)+2/7 3[3*11+2]/7 3[33+2]/7 3*35/7 105/7 15.

Nnesha (nnesha):

first P \(\huge\color{green}{{\rm P}}\)arentheses distribute (5+6) by 3

Nnesha (nnesha):

\(\color{blue}{\text{Originally Posted by}}\) @Surhur 3[3(5+6)+2/7 3[3*11+2]/7 3[33+2]/7 3*35/7 105/7 15. \(\color{blue}{\text{End of Quote}}\) how did you get 3 ??? front of [ ]

Nnesha (nnesha):

|dw:1427078586431:dw| there isn't any 3

Nnesha (nnesha):

so 35/7 ?

OpenStudy (acxbox22):

|dw:1427078620992:dw|

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