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Help with trig equations
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Solve the following equation on the interval [0, 360°]: 3sin2x =-2cos^2(2x)
Analyze this question. What do you think the method should be to solve the question?
good question for @dtan5457 to look at too :)
Yeah! He will get some practice too! :)
Hmm we could first add 2 to both sides
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Okay, go on!
so we would get \[5\sin(2x)=\cos^2(2x)\]
How did you get to this?
|dw:1427082718555:dw|
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