Question

Help with trig equations

Answer 1

Solve the following equation on the interval [0, 360°]:

3sin2x =-2cos^2(2x)

Answer 2

Analyze this question. What do you think the method should be to solve the question?

Answer 3

good question for @dtan5457 to look at too :)

Answer 4

Yeah! He will get some practice too! :)

Answer 5

Hmm we could first add 2 to both sides

Answer 6

Okay, go on!

Answer 7

so we would get \[5\sin(2x)=\cos^2(2x)\]

Answer 8

How did you get to this?