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by using the cylinder shell the volume of the solid when the region enclosed by y=x^2, x=2, x=3, and y=0 is revolved about the y-axis.
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a drawing tends to be quite helpful for these
|dw:1427083358479:dw|
recall that a shell is just the lateral area of a cylndar, so circumference times height
\[\int 2\pi rh\]
integrate: 2pi rh since r = x, and h=x^2 this simplifies to just integrate: 2pi x x^2 from x=2 to 3
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