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Mathematics 17 Online
OpenStudy (narissa):

Can someone check my answer ?

OpenStudy (anonymous):

Sure

OpenStudy (narissa):

OpenStudy (anonymous):

can u helpme with this please

OpenStudy (igreen):

That is correct.

OpenStudy (anonymous):

120/200 = 60/100 = 60% so your correct :)

OpenStudy (igreen):

60% of 200 = 0.60 * 200 = 120

OpenStudy (anonymous):

A flower shop received a total of 24 boxes of roses. Each box had red, yellow, and white roses. There were 16 roses in each box. The shop received a total of 125 red roses and 112 yellow roses. How many white roses did the shop receive?

OpenStudy (anonymous):

i'll givce u a medal

OpenStudy (narissa):

yhanks

OpenStudy (igreen):

@tracy68 Make your own question.

OpenStudy (anonymous):

Man its so nice to get good help these days.

OpenStudy (anonymous):

i just said that can u help me

OpenStudy (igreen):

I can help, but you have to make your own question.

OpenStudy (igreen):

Paste it into the "Ask a question...' box.

OpenStudy (anonymous):

it wont let me post it

OpenStudy (igreen):

What happens?

OpenStudy (anonymous):

theer is no post button on the bottm

OpenStudy (anonymous):

.............................................

OpenStudy (igreen):

Reload your page and try again.

OpenStudy (anonymous):

Try the problem again the answer is c or d ill tell you if you got it right @narissa

OpenStudy (narissa):

can i close this i have others to be checked?

OpenStudy (anonymous):

sure

OpenStudy (igreen):

@tracy68 I just made a question for you to post your question in..I tagged you.

OpenStudy (anonymous):

where is that at i'm new to thsi

OpenStudy (anonymous):

24X16=384 112+125=237 384-237=147 @tracy68

OpenStudy (narissa):

OpenStudy (anonymous):

First 75% = 108, so u find 25% of that number which is 108 divided by 3 since 75 divide by 25 = 3. That will get you 36. So to find out 100% you would need to take 25%X4 which is 36X4 giving you 144 so you are correct :)

OpenStudy (anonymous):

can someone help with question please I'll give medals

OpenStudy (anonymous):

what do you need help on @tracy68

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