Question

*WILL GIVE A MEDAL!!!* -- TRIG

PLEASE EXPLAIN!

Answer 1

What is the period of the function \[y = \frac{ 1 }{ 2 } \sin (\frac{ x }{ 3 } - \pi)\] ?

Answer 2

period is 2pi/the number of in front of x there

Answer 3

\[y=A \sin(Bx-C)=D \]
period is 2pi/B

Answer 4

y=sin(x) on [0,2pi] looks like
This is one period
if we play with the number in front of x
y=sin(Bx) we play with the period