Question

MEDAL!!!
I'm stuck!!
log

Answer 1

\(\bf -log_5(3r)+4=3\implies -log_5(3r)=-1\implies log_5(3r)=1
\\ \quad \\
log_{\color{brown}{ a}}{\color{blue}{ b}}=y\iff {\color{brown}{ a}}^y={\color{blue}{ b}}\qquad thus
\\ \quad \\
log_{\color{brown}{ 5}}({\color{blue}{ 3r}})=1\implies ?\)

Answer 2

\[\log_5(x) = \frac{ \log(x) }{ \log(5) }\]

Answer 3

did i do it right?