Question

find the coordinates of the vertex for the parabola defined by the given quadactic function f(x)=11(x-5)^2+9

Answer 1

Your quadratic is in vertex form such that: \(y=a(x-\color{red}{h})^2+\color{red}k\)

Answer 2

Now just relate this your equation and match up terms.\[y=a(x-\color{red}{h})^2+\color{red}k\]\[y=11(x-\color{red}5)^2+\color{red}9\]