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Mathematics 11 Online
OpenStudy (anonymous):

let xy=5 and let dy/dt=5 find dx/dt when x=4 I solved for y first and got 5/4: xy=5 y=5/x => 5/4 (x)(dy/dt) + (5/4)(dx/dt) = 0 (4)(5) + (5/4)(dx/dt) = 0 => 20 + (5/4)(dx/dt) = 0 dx/dt = -20/(5/4) Webworks is saying it is wrong though?

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