WILL GIVE MEDAL
A box has 8 beads of the same size, but all are different colors. Tamy draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times. What is the probability that Tamy would pick a red bead on the first draw, then a white bead, and finally a red bead again?
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OpenStudy (anonymous):
okay so
OpenStudy (anonymous):
1/8
OpenStudy (anonymous):
no wait
OpenStudy (anonymous):
it could be 3/8
OpenStudy (anonymous):
no you need to count the possibility
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OpenStudy (anonymous):
Its multiple choice, 1 over 4096
1 over 512
1 over 64
1 over 8
OpenStudy (anonymous):
Well u help them then i tried -_-
OpenStudy (anonymous):
@helper2222
OpenStudy (anonymous):
do you know how to find the possibility
OpenStudy (luffingsails):
Consider that you are drawing with replacement (very important to note).
So, what you are looking at is (in words):
Probability of drawing red AND
Probability of drawing white AND
Probability of drawing red.
How do you calculate P(A) and P(B)?
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OpenStudy (anonymous):
dude he is not here no more
OpenStudy (luffingsails):
lol... well. If anyone else is looking then.
OpenStudy (anonymous):
NO PLZZ HELP I HAVE SAME QUESTION! @helper2222 @luffingsails
OpenStudy (anonymous):
I NEED THE ANSWER TO THIS QUESTIOOOON @dan815 @Preetha