Question

what is the solution of the equation
-3x^2+6x=-12

a. x=-1+sqrt5
b. x=1+sqrt5
c. x=-1+i sqrt5
d. x=1+i sqrt5

Answer 1

\[\huge\rm x = \frac{ -b \pm \sqrt{b^2 -4ac} }{ 2a }\] quadratic formula
first add 12 both side
to write that equation in standard form
Ax^2 + Bx+C=0
and substitute a ,b,c values into the formulathen solve :-)

Answer 2

ok..

Answer 3

a= ?
b= ?
c= ?

Answer 4

-3x^2
6x
-12

Answer 5

?

Answer 6

coefficient at front of variable

Answer 7

\[\huge\rm \color{green}{A}x^2 +\color{green}{B}x +\color{green}{C}=0\]
c is constant
x^2 and x is variable
a and b just numbers at front of variables

Answer 8

k

Answer 9

\[-3x^2 +6x = -12 \]
first write it instandard form
add 12 both side