Question

Trigonometric Proofs, LAST ONES
\[\frac{ \sin^4(\gamma)-\cos^4(\gamma) }{ \sin(\gamma)-\cos(\gamma)}=\sin(\gamma)\cos(\gamma)\]
and
\[\frac{ (1+\cos(A))(1-\cos(A))}{ \sin(A) }=\sin(A)\]

Answer 1

I have no idea how to cancel out more than 1 exponent and theres no identities that match >.<

Answer 2

HI!! (again again)

Answer 3

xD

Answer 4

more algebra i see ...

Answer 5

\[\frac{b^4-a^4}{b-a}=\frac{(b^2-a^2)(b^2+a^2)}{b-a}\] is a start i.e. factor

Answer 6

now we know what \(b^2+a^2\) is right ??

Answer 7

Oh yes, cause that equals 1

Answer 8

help misty

Answer 9

ok good
so we have
\[\frac{b^2-a^2}{b-a}\] factor again

Answer 10

so then its just left with (a^2-b^2) on top

Answer 11

factor the difference of two square, cancel, have a beer

Answer 12

Ah thank you. That makes so much sense.

Answer 13

nice \(\gamma\) btw

Answer 14

ha thank you. It was on my assignment so I assumed I should use it

Answer 15

second one is real real (real) easy

Answer 16

Oh yeah? am i totally missing it?

Answer 17

yes you are

Answer 18

misty i really need help me plzz

Answer 19

\[(1-a)(1+a)=1-a^2\]

Answer 20

\[\frac{1-\cos^2(\xi)}{\sin^2(\xi)}\]

Answer 21

oops \[\frac{1-\cos^2(\xi)}{\sin(\xi)}\]

Answer 22

that makes sense, but how do you get it to isolate sin?

Answer 23

oh wait

Answer 24

and guess what \(1-\cos^2(\xi)\) is equal to ?

Answer 25

the indentity!

Answer 26

lol

Answer 27

sin^2

Answer 28

then cancel ahhh yes

Answer 29

cancel be done with your homework

Answer 30

thank you so much, ah finally finished

Answer 31

\[\color\magenta\heartsuit\]

Answer 32

you've been awesome!

Answer 33

(blush)