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solve log2(35x)-log2(7)=3
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apply quotient property \[\huge\rm log_b x \color{red}{-} \log_b y = \log_b \frac{ x }{ y }\] if there is negative sign you can change that to division subtraction ---->division addition .-----> multiplication
ya thats as far as I got @Nnesha
do you times the 3 by the 7?
\[\huge\rm log_2 ( 35x) - \log_2 (7) =3\] after quotient property change log to exponential form
ok so 2^3=35x/7
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yep!!
so after all the calculations it would be 1.6?
yep that's right
wow im making these a lot harder than they really are haha. thanks again.
yep these type of question r very easy
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