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\[\int\limits ( x^2\sqrt{1+x^2})^-1 dx\]
is it 1/the whole expression.... power -1
correctly write the question
wait
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\[\int\limits (x^2 \sqrt{1+x^2})^{-1}dx\ \ sorry \\ for\\ error\]
put x=tan t
how u recognised?
because 1+tan2t = sec2t
square... not 2
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so sec2t dt = dx
then?
you try on pls
okay
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