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A spinner with nine equal sized sections numbered one to nine is spun once. What is the probability that the spinner will land on a number that is NOT a multiple of 3? A. 2/3 B. 1/3 C. 7/9 D. 5/9
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well first count how many spots there are in total? so that would be 9... Next count how many multiple of 3's are in 9
3,6,9 therefore there is 3 outcomes where you'll get a multiple of 9, which means all the rest are NOT a multiple or 6
so the probability of NOT landing on a multiple of 9 would be 6/9
2/3
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