Question

I need a solution step by step

d/dx
Derivative of trigonometric functions
y=cot x - tan x

Answer 1

so, do you happen to have the derivative of cotangent memorized?

Answer 2

If not, check out this page(if we do not want to have to derive it every time, it is beneficial to have them memorized) http://www.sosmath.com/calculus/diff/der03/der03.html

Answer 3

\(\bf \cfrac{d}{dx}[cot(\theta)]=-csc^2(\theta)\qquad \cfrac{d}{dx}[tan(\theta)]=sec^2(\theta)\)

Answer 4

well.. or \(\bf \cfrac{d}{dx}[cot(x)]=-csc^2(x)\qquad \cfrac{d}{dx}[tan(x)]=sec^2(x)\)

for that matter

Answer 5

@pearlss can you please respond?

Answer 6

or blink twice for yes
or blnk once for no
or blink three times for maybe