Mathematics
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OpenStudy (darkbluechocobo):
Help with law of sines
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OpenStudy (darkbluechocobo):
Use the Law of Sines to solve (if possible) the triangle for the value of c. Round answers to the nearest tenths. A = 18.92°, a = 48.35 yd, b = 105 yd
OpenStudy (darkbluechocobo):
|dw:1427400369274:dw|
OpenStudy (darkbluechocobo):
We can't really solve for c.. Cane we?
OpenStudy (darkbluechocobo):
@xapproachesinfinity Could you assist?
OpenStudy (darkbluechocobo):
We can't solve for c because we don't have angle B
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OpenStudy (darkbluechocobo):
\[180-B-18.92\]
OpenStudy (darkbluechocobo):
we have to have angle B to get angle C which is very necessary in finding c
OpenStudy (freckles):
you can solve for angle B though using law of sines
OpenStudy (darkbluechocobo):
really?
OpenStudy (freckles):
then we can find angle C using the formula you posted above
then you can find side c using law of sines
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OpenStudy (darkbluechocobo):
so \[\frac{ 48.35 }{ \sin18.92 }=\frac{ 105 }{ sinB }\]
OpenStudy (freckles):
so b is 105 not 10
OpenStudy (darkbluechocobo):
\[B=\sin ^{-1}\frac{ 105\sin18.92 }{ 48.35 }\]
OpenStudy (darkbluechocobo):
44.76 degrees?
OpenStudy (freckles):
That is what I have as well
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OpenStudy (darkbluechocobo):
180-44.76-18.92=116.32
OpenStudy (darkbluechocobo):
|dw:1427401469623:dw|
OpenStudy (freckles):
yep
not you get to use law of sines one more time to find c :p
OpenStudy (darkbluechocobo):
so\[\frac{ 48.35 }{ \sin18.92 }=\frac{ c }{ \sin116.32 }\]
OpenStudy (darkbluechocobo):
\[c=\frac{ 48.35\sin116.32 }{ \sin18.92 }\]
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OpenStudy (darkbluechocobo):
133.7 yds?
OpenStudy (freckles):
yes that is what I have if I round what I have to the nearest tenths
OpenStudy (darkbluechocobo):
woop. This stuff is so much more easier than fundamentals
OpenStudy (freckles):
You are doing awesome.
You are solving these equations like no one's business.
OpenStudy (darkbluechocobo):
Thanks man :p