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Find the product of the complex numbers. Express your answer in trigonometric form. z1=5(cos(25)+i sin(25) z2=2(cos(80)+i sin(80)
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I think its either A. or B.
hint: \[\begin{gathered} {z_1} = 5{e^{i25}} \hfill \\ {z_2} = 2{e^{i80}} \hfill \\ {z_1} \times {z_2} = 5 \times 2 \times {e^{i25}} \times {e^{i80}} = ...? \hfill \\ \end{gathered} \]
do I take 80-25=55 360-55= 305 is that how you solve this
\[{e^{i25}} \times {e^{i80}} = {e^{i\left( {25 + 80} \right)}} = {e^{i105}}\]
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we have to sum 25 with 80
oh so b. 105 then
ok!
if you were looking for the quotient would you subtract
yes!
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