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this circle has a circumfrence of 60 centimeters. the measure of
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circ.=2*pi*r =60(given) arc is fraction circ. =72/360= 1/5 so 1/5 *2*pi*r =1/5 (60)=12
what about the second question?
surface area of sphere 4*pi*r^2 r=20/2=10 r^2=10*10=100 put it in 4*pi*100=400pi make sure you understand or let me know
quadrilateral GHIJ has congruent diagonals that bisect one another. What kind of quadrilateral must GHIJ be? rectangle non-rectangle parallelogram non-parallelogram kite trapezoid
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don't know that sorry
a square has equal diagonals that bisect
I suppose that a square is a rectangle I'll go for that
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