Question

Using a directrix of y = -2 and a focus of (1, 6), what quadratic function is created?

Answer 1

HI again!!

Answer 2

you need to know two things,
a) what it looks like and
b) the vertex

Answer 3

f(x) = 1/16(x - 1)^2 + 2

Answer 4

Is that the answer ^^ can you please check?

Answer 5

vertex is \((1,2)\)

Answer 6

oh yeah your answer is right

Answer 7

Oh ok. Thanks! :)

Answer 8

\[\color\magenta\heartsuit\]

Answer 9

\[4p(y-k)=(x-h)^2\]

Answer 10

\[16(y-2)=(x-1)^2\]