Question

@Agl202

Answer 1

\[\frac{ \sec^2x-\tan^2x }{ \csc x }\]

Answer 2

HI!!

Answer 3

HI :)

Answer 4

:( and this one

Answer 5

does it help to know that
\[\sec^2(x)-\tan^2(x)=1\]?

Answer 6

It's okay, @Agl202 ☺

@misty1212 No, I don't understand this one at all. :/

Answer 7

@misty1212 OH! Wait, so you are saying that if sec^2(x)−tan^2 (x)=1
Then it becomes 1/cos(x)? Which would equal to sec(x?