Question

helpful steps please,
Find the exact solutions of the equation in the interval [0, 2pi)?
Sin^2 2x=1
Solve the equation for solutions in the interval [0 degrees, 360 degrees)?
sqrt(3) Sec2(theta)=2

Answer 1

are these two separate questions?

Answer 2

Yes they are both separate

Answer 3

sin^2 (2x)=1 take square root of both sides
sin(2x)=1
2x=asin(1)
x= +-asin(1)/2

Answer 4

so then is it pi/4, 3pi/4, 5pi/5 and 7pi/4 ?

Answer 5

sin (2x)=-+1
2x=pi/2, 3pi/2

Answer 6

yes

Answer 7

then for the second one is it 15, 165, 195 and 345 degrees?