Question

In the diagram below, find 0 to the nearest degree. (Diagram will be in response)

Answer 1

the unknown side in your triangle is found using pythagoras
(14*14)-(9*9) =x^2
196-81=x^2
115=x^2
so x=10.72
cos angle (1) =10.72/14 =0.765 look up the angle =40 deg.
sin(2) angle =10.72/14 0.766 ' " " " =50deg
hope you understand this