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Assistance with Law of sines pls
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The information in the following problem allows you to construct 2 triangles, find C1 and C2. B = 40°, a = 2.2 m, b = 1.7 m
|dw:1427510099197:dw|
\[A=\sin^{-1}\frac{ 2.2\sin40 }{ 1.7 }\]
good, find the value in degrees maybe
56.3
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180-40-56.3
C=83.7
well C1=83.7
How would you find C2?
C2/sin83.7=2.2/sin56.3
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hey
did you get A = 56.3 ?
you must get two values for A that are less than 180
A = 56.3, 123.7
the corresponding values for C would be C = 83.7, 16.3
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