Question

Help! What would the vertex of this function be? h(x)=(x+2)^2-1

Answer 1

the equation is already in vertex form, the general form is

\[y = (x + h)^2 + k\]

where (h, k) is the vertex.

You need to compare this to your question to find the vertex

Answer 2

Would it be 2,-1?

Answer 3

that's correct (2, -1)