Question

Use the quadratic formula to solve the equation
2x^2-3x+8=0

a. 3+i sqrt110/4
b. 3+sqrt55/4
c. 3+i sqrt55/4
d. 3+i sqrt55/2

Answer 1

\[\huge\rm x = \frac{ -b \pm \sqrt{b^2 -4ac} }{ 2a }\]
quadratic formula to find solution

Answer 2

do you know what a b or c are in the quadratic equation

Answer 3

no

Answer 4

is it
2
-3
8

Answer 5

\[\huge\rm \color{red}{A}x^2 +\color{red}{B}x +\color{red}{C}=0\]
quadratic equation A b are coefficient number
and C is constant

Answer 6

@Omgthatgirl
yes those are the correct valuesd for a,b & c

now put them into th eformula and solve the 2 values for x

Answer 7

ok lett me do that

Answer 8

ok i got -55 as the sqrt

Answer 9

-55 is correct for that part

but I think you have not typed the answer options correctly

should be +/- where oyu have + (I think)

Answer 10

separate -1 and 55
and remember \[\huge\rm \sqrt{-1} = i\]

Answer 11

thats how it actually is not a +

Answer 12

yeah ik :)
okay so
factor of -55
-1 and 55 so now you can change sqrt of -1 to i right
bec \[\sqrt{-1} =i\]