Question

Find the first three output values of the fractal generating function f(z)=z^2+2+i

a. 2+i, 2+5i, -2595+205i
b. 2+i, 5+5i, -2595+205i
c. 2+i, 5+5i, 2+51i
d. 5+5i, 2+51i, -2595+205i

Answer 1

is the 'seed' value z = 0 ?

Answer 2

i thnk so

Answer 3

ok plug in z = 0 into f(z)

Answer 4

k

Answer 5

i think its d

Answer 6

f(0) = 0^2 + 2 + i = 2 + i
so the first value is 2 + i

f(2+i) = (2+i)^2 + 2 + i = (2 + 2i)(2+2i) + 2 + i = 5 + 5i

Answer 7

so the next ouput is 5 + 5i

Answer 8

wourl the third be -2595?