Question

How would I graph this system of inequalities,
35x+3y<=200
x>=2
y>=20
, onto a graph like this http://media.apexlearning.com/Images/201306/24/0a68ca9c-2921-4020-aa91-12fcbd0f27b7.jpg

Answer 1

Draw a vertical line at x = 2
Draw a horizontal line at y = 20
Since 35x+3y<=200,
\[3y \le -35x+200\]
\[y \le \frac{-35}{3}x+\frac{200}{3}\]
Mark the y intercept on the y axis and from there go down 35 and right 3 and draw that line.

Answer 2

Thanks a million!

Answer 3

yw