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Factoring help! X^3 !!
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\[x^3-2x^2-8x\], How do I find factor of something like this?
Extract the x which is common to all terms getting x(x^2 - 2x -8) now factor that 2nd factor\[x ^{2}-2x-8\]
It will factor nicely.
okay, I will try to work it out, gimmie moment
x*(x-2)(x+4)
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Trying is half (or even more) of it. I'll be here.
is that right? x(x-2)(x+4)
Got a sign problem you want a -2x what you wrote will give a +2x
You're almost there.
yea,reversed, damn, I have got it that way on ppaper!
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just swap + with - and - with + so x(x+2)(x-4)
Excellent. A medal for you for you effort and success.
Thank you a lot. Have a nice day.
You too.
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