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Mathematics 7 Online
OpenStudy (anonymous):

Algebra 2 semester 2 help please? Rational Functions. http://prntscr.com/6mzt4u

OpenStudy (amistre64):

16 is substitution, when n=1/2 does it make a true statement rational can be thought of as 'looks like a fraction' rational functions are just glorified fractions and all the rules of fractions apply to them

OpenStudy (anonymous):

I don't understand how to do 17. :o

OpenStudy (amistre64):

well, the simplest thing to do would be to clear the denominators; so multiply thru by 5-p

OpenStudy (amistre64):

when does: 5-p^2 = -2(5-p)

OpenStudy (amistre64):

might need to know the quadratic formula to solve for p if you aint to good at factoring

OpenStudy (anonymous):

this is so difficult lol sigh. thank you

OpenStudy (anonymous):

http://prntscr.com/6mzzq0 ?

OpenStudy (anonymous):

that looks really wrong

OpenStudy (amistre64):

you dropped the negative on the 2 at the start ...

OpenStudy (amistre64):

and you forgot to ... let me spot a few things for you

OpenStudy (amistre64):

5 - p^2 = -2(5-p) 5 - p^2 = -10+2p - p^2 =2p -15 0 = p^2 +2p -15

OpenStudy (anonymous):

Whaaaat :o Oh man I should not have started this quiz

OpenStudy (amistre64):

5 and -3 are factors of -15 that add up to 3, so we can facotr this into 2 pieces 0 = (p-3)(p+5) now when does p-3=0? when does p+5=0?

OpenStudy (anonymous):

p=3 and p=-5.

OpenStudy (amistre64):

thats the solutions for p as long as 5-p doesnt equal 0 we are good to go ... cant divide by a zero after all. 5--5=10 so we are good

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

so much :)

OpenStudy (amistre64):

good luck with it

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