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(A ∩ B) ∪ (C ∩ D) = (A ∩ D) ∪ (C ∩ B) help prove the following statement?
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did you try to distribute
Distributive laws $$\Large { A \cup (B \cap C) = (A \cup B) \cap (A \cup C)\\\ A \cap (B \cup C) = (A \cap B) \cup (A \cap C)\ }$$
yeah, it gives me (A ∪ C) ∩ (A ∪ D) ∩ (B ∪ C) ∩ (B ∪ D) . After I could end up with (A) ∩ ( D) ∩ ( C) ∩ (B ) and group them, but im still missing the union symbol :/
forget what I just said, use inference rule! thank you
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