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OpenStudy (anonymous):
please help
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OpenStudy (anonymous):
OpenStudy (amistre64):
we need to determine EG before we can determine EC
OpenStudy (amistre64):
or, we can go about this in a more general way to determine a formula we can use
OpenStudy (amistre64):
typos ... let me edit
OpenStudy (amistre64):
the pythag thrm tells us that a^2 + b^2 = c^2
therefore let EG = c
c^2 + z^2 = (EC)^2
^^^
a^2 + b^2 + z^2 = (EC)^2
^^^
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OpenStudy (amistre64):
we have 8 5 and 12, square them add them and then sqrt the sum
OpenStudy (anonymous):
the square root of 8 is 2.82 the square root of 5 is 2.23 and the square root of 12 is 3.46
OpenStudy (amistre64):
squre first
8^2 + 5^2 + 12^2 = (EC)^2
64+25+144 = (EC)^2
144+89 = (EC)^2
233 = (EC)^2
OpenStudy (amistre64):
since 15^2 = 225, im gonna guess this is a little over 16
OpenStudy (anonymous):
okay sooo uhm what do we do next
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OpenStudy (amistre64):
click the one thats a little over 15 ....
OpenStudy (anonymous):
ohh okay lol i thought there where more steps haha so its 15.3
OpenStudy (amistre64):
(EC)^2 = 233
15^2 < EC^2 < 16^2
225 < 233 < 256
OpenStudy (amistre64):
15.3 is fair enough yes :)
OpenStudy (anonymous):
thanks alot CX
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OpenStudy (amistre64):
good luck
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