what is the area of the rectangle? round to the nearest square inch?
find the bottom length of the triangle
what grade and class?
given that the area of a rectangle = length * width. also the triangle formed with that diagonal is a right triangle
okay sso i would do x^2 x 5^2??
Do you see that the diagonal separates the rectangle into two identical right triangles?
yes
The diagonal of 8 inches is the hypotenuse of the triangle whose one leg is 5 in.
the other leg is the one you need to find in order to calculate the area of the rectangle.
okay how would i find it?
Use the pythagorean theorem where the hypotenuse squared is equal to the sum of the legs squared.
\[8^{2}=5^{2}+x ^{2}\]
8^2 is 64 so i have to find 5^2 + x^2= and make it equal 64?
Yes, use algebra to solve \[64 = 25 + x ^{2}\]
i tink its either 6^2 or 7^2
think
You know the drill, no different than the many similar problems that you have been solving al day
\[x ^{2}=64-25\]
39*39 right?
or square root of 39?
Just a plain ole 39 that is what x squared is, but you need to find x....yes, that's the ticket.
6.24
yaaa ur the best
Now you still need to find the area of the rectangle so multiply the two sides.\[A = 5 \sqrt{39}\]
31.2?
Don't forget to round off to the nearest square inch. Good night and good luck, the day has ended for me. yes.
thank you :)))))))))))))))))
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