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Solve the triangle A = 33°, a = 20, b = 13
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what type of triangle our we looking at?
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are you familiar with laws of sine?
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\(a/sinA = b/sinB = c/sinC \) or \(sinA/a = sinB/b = sinC/c\)
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RESPOND
\(\large\frac{sinB}{13} = \frac{sin(33)}{20}\) make sure your calculator is set properly
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