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Mathematics 19 Online
OpenStudy (anonymous):

http://prntscr.com/6n5zc2

OpenStudy (perl):

we are given the formula : $$ \Large{ 3\cdot 7^{n-1} \\~\\ \text {plug in n=1,2,3}\\~\\ 3\cdot 7^{1-1}, 3\cdot 7^{2-1}, 3\cdot 7^{3-1} } $$

OpenStudy (anonymous):

21, 21^1

OpenStudy (perl):

use order of operations when you simplify

OpenStudy (anonymous):

so 21

OpenStudy (perl):

are you looking at the third term?

OpenStudy (anonymous):

yes

OpenStudy (perl):

$$ \Large 3\cdot 7^{3-1} = \Large 3\cdot 7^{2} = 3\cdot 49 $$

OpenStudy (anonymous):

49x3 is 147

OpenStudy (perl):

correct.

OpenStudy (anonymous):

how did u get 49 tho

OpenStudy (perl):

$$ \Large{ 3\cdot 7^{3-1} \\ = 3\cdot 7^{2} \\=3 \cdot 7 \cdot 7 \\= 3\cdot 49 } $$

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so 21,49

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