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|dw:1427743641293:dw|
Given that ,point \(A\) lies between \(B\) and \(D\) , \(AC=AD\) .Prove that \(\angle BCD>\angle BDC\)
should be easy
|dw:1427744010000:dw|
yes its from \(9th\) grade but i still can;t figure it
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base angles of isosceles triangle are equal
hahahah
i am silly
i forget that \(\angle ADC=\angle BDC\)
its embarasing
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\[\begin{align}\angle BCD &= \angle BCA + \angle ACD\\~\\ &=\angle BCA + \angle ADC\\~\\ &=\angle BCA + \angle BDC\\~\\ &\gt \angle BDC \end{align}\]
that looks neat way
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