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f(x) = -x^4-7x^3+5x-4 Find where concaave up and concave down. I've found the inflection points of 0, 7/2. How do I know the intervals where concave up and concave down?
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Have you taken the second derivative and found the critical points, yet?
Well, you clearly did because you already found the inflection points :)
So, when you already found the critical points if you have f"<0 then that is concave down if you have f">0 then it is concave up. |dw:1427783568474:dw|
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