Question

is this correct?
http://snag.gy/eKbyA.jpg

Answer 1

no its C.

Answer 2

7 is C? right?

Answer 3

almost, but step c. should be:

\[\frac x6 = 13\]multiply both sides by 6 (valid because of the multiplication property)\[\frac x6 \times 6= 13\times 6\]\[x=13\times6\]

Answer 4

thank you! and for the other?

Answer 5

for question 8.

use the fact that vertically opposite angles are equal

3x-10 = 149

add ten to both sides

... = ...

divide both sides by three

... = ...

Answer 6

13x-20=
?

Answer 7

3x-10 = 149

add ten to both sides

3x-10+10 = 149+10

. . . = . . .

Answer 8

159?

Answer 9

3x-10+10 = 149+10
3x+0 = 159
3x = 159

Now, divide both sides by three

. . . = . . .

Answer 10

53?

Answer 11

3x = 159
3x/3 =159/3
x = 53

yes

Answer 12

god bless u <3