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which is the extraneous solution of -x = sqrt(2x +15)
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|dw:1427826760433:dw| a) -5 b) -3 c) 3 d) 5
What is the extraneous solution
square both sides
You basically want to see which of those is a solution to \[x^2=2x+15 \text{ but \not a solution to } -x=\sqrt{2x+15}\]
So the answer is 5
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sounds great! :)
that are two soluitions to x^2-2x-15=0 (x+3)(x-5)=0 x=-3 or x=5 we see the 5 definitely won't work because there is no way sqrt() will produce a negative number
\[-x=\sqrt{2x+5} \text{ means } x \text{ is negative }\]
anyways great job
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