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OpenStudy (michele_laino):
here we have a similar problem, namely we have to determine the coefficient a and b of the subsequent relationship (linear):
y=ax+b
OpenStudy (anonymous):
c
OpenStudy (anonymous):
c
OpenStudy (anonymous):
each time add 4.80 to the number before
OpenStudy (michele_laino):
in order to that I will use the data of your problem:
\[\left\{ \begin{gathered}
204.80 = 4a + b \hfill \\
209.60 = 8a + b \hfill \\
\end{gathered} \right.\]
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OpenStudy (michele_laino):
from the first equation I get:\[b = 204.8 - 4a\]
OpenStudy (howard-wolowitz):
yeah thats what i got the 204.8
OpenStudy (michele_laino):
then I substitute it into the second equation:
\[209.6 = 8a + 204.8 - 4a\]
OpenStudy (howard-wolowitz):
and i solve that foe a correct?
OpenStudy (michele_laino):
yes!
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OpenStudy (michele_laino):
it's all ok now!
OpenStudy (howard-wolowitz):
1.2
OpenStudy (howard-wolowitz):
Great!
OpenStudy (michele_laino):
wait please, I'm going to check your result
OpenStudy (michele_laino):
that's right!
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OpenStudy (michele_laino):
now, we have to compute the value of b
OpenStudy (howard-wolowitz):
and we get $214... something i know
OpenStudy (michele_laino):
in order to that, I substitute a=1.2 into the expression for b, namely:
\[b = 204.8 - 4a = 204.8 - 4 \times 1.2 = ...?\]
OpenStudy (michele_laino):
I think b=200
OpenStudy (michele_laino):
204.8 - 4.8 = 200
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OpenStudy (howard-wolowitz):
ok one sec
OpenStudy (howard-wolowitz):
but thats been solved and i cant solve that its already done
OpenStudy (michele_laino):
It is the first time that I solve this problem
OpenStudy (howard-wolowitz):
hmm ok one sec so b=200 then what do we do? somehow pug it in
OpenStudy (michele_laino):
our function is:
y= 1.2x+200
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OpenStudy (michele_laino):
now we have to set x=12, and compute the correspondent value og y, namely:
y= 1.2*12+200=...?
OpenStudy (howard-wolowitz):
ok
OpenStudy (howard-wolowitz):
y=214.4
OpenStudy (michele_laino):
congrats! you got the right answer
OpenStudy (michele_laino):
so what is the right option?
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