Mathematics
14 Online
OpenStudy (anonymous):
Find the product of (x + 3)(x - 3).
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
!!!!!!!!!!!!!!!!!!!medal and fann!!!!!!!!!!!!!!!!!!!!!
OpenStudy (onepieceftw):
Use foil. First term, outer term, inner term, last term.
OpenStudy (onepieceftw):
x times x
x times -3
3 times x
3 times -3
OpenStudy (anonymous):
x^2 - 6x + 9
x^2 + 6x + 9
x^2 + 9
x^2 - 9
OpenStudy (onepieceftw):
Very good!
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
those r the choices
OpenStudy (onepieceftw):
You can do this calculation. Which one do you think it is?
OpenStudy (anonymous):
not c or d
OpenStudy (anonymous):
and it is negative s a ?
OpenStudy (anonymous):
so*
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (onepieceftw):
Try again.
OpenStudy (anonymous):
3*3 is 9 not 6 sorry umm it is d
OpenStudy (onepieceftw):
multiply the terms and simplify like terms.
how can x^s-3x+3x-9 be simplified?
OpenStudy (onepieceftw):
x^2*
OpenStudy (anonymous):
hold on lemme work it out
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
OpenStudy (onepieceftw):
\[x \times x = x^2\]
\[x \times -3 = -3x\]
\[3 \times x = 3x\]
\[3 \times -3 = -9\]
OpenStudy (onepieceftw):
-3x +3x =0
OpenStudy (anonymous):
yeah thats what the attachmeny says
OpenStudy (onepieceftw):
So x^2-9 is your simplified form
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
co it is d
OpenStudy (anonymous):
so*
OpenStudy (anonymous):
i sqaid that earlier
OpenStudy (onepieceftw):
Yes. This question can also be written as (x-3)^2 which makes it a bit easier. I don't know if you've learned that yet.
OpenStudy (onepieceftw):
I wanted to you to do the work without guessing.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i wasnt guessing i actualy thpught it was d
OpenStudy (onepieceftw):
wanted you*