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The plane through the point (−1, 4, 2) that contains the line of intersection of the planes 4x−y+z−2 = 0 and 2x + y − 2z − 3 = 0.
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find the line of intersection ....... cross the normals and attach it to a common point
what does crossing the normals give me?
it gives you the vector for the line of intersection
ok i found the line , how do i get the plane equation ?
you need 2 vectors, one of them is the line vector, the other is a vector from a point in the line to the given point. cross those vectors and you get the normal to the plane you need
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ok now i get it thanks a lot
youre welcome
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