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Mathematics 7 Online
OpenStudy (18jonea):

Compare the quantity in Column A with the quantity in Column B. https://nnds-li.brainhoney.com/Resource/19791663,8AD/Assets/assessmentimages/geo%20part%202%20u1l7%205.jpg The quantity in Column A is greater. The two quantities are equal. The quantity in Column B is greater. The relationship cannot be determined based on the given information. @thesmartone @aaronq

OpenStudy (igreen):

Use the pythagorean theorem.

OpenStudy (igreen):

\(a^2 + b^2 = c^2\) Where 'a' and 'b' are the two legs and 'c' is the hypotenuse. Plug in what we know: \(7^2 + 7^2 = c^2\)

OpenStudy (igreen):

7^2 = ? @18

OpenStudy (igreen):

@18jonea *

OpenStudy (18jonea):

what is the answer?

OpenStudy (18jonea):

@iGreen

OpenStudy (igreen):

What's 7^2?

OpenStudy (18jonea):

49

OpenStudy (18jonea):

@iGreen

OpenStudy (18jonea):

@jagr2713

OpenStudy (18jonea):

@bohotness

OpenStudy (igreen):

Yes, so we have: \(49 + 49 = c^2\) 49 + 49 = ?

OpenStudy (igreen):

@18jonea

OpenStudy (igreen):

Can you add 49 + 49? @18jonea

OpenStudy (18jonea):

98 but that isnt one of my options

OpenStudy (igreen):

Find the square root of 98 now

OpenStudy (igreen):

Yes, we aren't done yet.

OpenStudy (18jonea):

o ok

OpenStudy (18jonea):

then what do me do next

OpenStudy (igreen):

\(\sqrt{98} =~?\) Simplify that

OpenStudy (igreen):

The square root of 98

OpenStudy (18jonea):

9.89

OpenStudy (18jonea):

so how do i simplify that

OpenStudy (igreen):

Okay, that's 'x', now let's find 'y'.

OpenStudy (igreen):

Use the Pythagorean Theorem again: \(a^2 + 4^2 = 9^2\) Simplify 4^2 and 9^2

OpenStudy (igreen):

@18jonea

OpenStudy (18jonea):

16=81

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