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For #4 you have set up your Pythagorean theorem wrong
AC^2+4^2=10^2
For #5 easiest way I know of is using trig functions, have you learned them?
so for #4 I subtract to find the answer? #5 yes I have or else I wouldn't even be doing this.
Was just curious because you attempted the Pythag again, it's not needed for this one :-) tangent = opposite / adjacent. tan20 = 30 / bc
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Ahh I see and sorry I'm a bit cranky today didn't mean to sound rude :] and was I right about #4 needing to subtract instead?
5. \[30 \cot (20 {}^{\circ})=82.4243 \]
AC^2 + 16 = 100 ac^2 = 84 ac = + or - sqrt(84)
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