Question

What is the magnitude of the angular acceleration of a 25.0 kg disk of radius .800 m when a net torque is applied to it of 40.0 N-m?

Answer 1

ok i got it wrong....i got 2.5, but the right answer is 5?? I=25(.8)^2=16 then plug in I so 40/16=angular acc, what did I do wrong?

Answer 2

If a small object rotates around a circle of radius r, then the momentvof inertia
I=mr^2

Answer 3

* moment of inertia

Answer 4

This formula will b changed for a rotating disc

Answer 5

I think u hv to use
I =0.5mr^2

Answer 6

Response plz!!!!!!!

Answer 7

where did you get .5?

Answer 8

oh nevermind! from the formula for a disk, thats what i am missing! thanks a bunch!!!! :D

Answer 9

U r most welcome!!!!!!