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Mathematics 12 Online
OpenStudy (howard-wolowitz):

ONE QUESTION!

OpenStudy (howard-wolowitz):

@Michele_Laino

OpenStudy (michele_laino):

hint: since \[\frac{A}{{{r^2}}} = \pi = constant\] I don't think that A varies directly with r

OpenStudy (michele_laino):

better is to say that A varies directly with r^2

OpenStudy (howard-wolowitz):

jointly is in fraction form correct?

OpenStudy (michele_laino):

yes I think so!

OpenStudy (michele_laino):

sincerely I think, namely the second option, since A doesn't varies inversely with r

OpenStudy (michele_laino):

oops..doesn't vary...

OpenStudy (howard-wolowitz):

so B?

OpenStudy (howard-wolowitz):

oh gotcha

OpenStudy (michele_laino):

yes!

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