WILL GIVE METAL!!!
A physics student stands at the top of hill that has an elevation of 37 meters. He throws a rock and it goes up into the air and then falls back past him and lands on the ground below. The path of the rock can be modeled by the equation y=-0.02x^2 + 0.8x+37 where x is the horizontal distance in the meters from the starting point on the top of the hill and y is the heigth in meters, of the rock above the ground. How far horizontally from its starting point will the rock land? Round your answer to the nearest hundredth?

*37.00m
*67.43m
*27.43m
*37.78m

Question

WILL GIVE METAL!!!
A physics student stands at the top of hill that has an elevation of 37 meters. He throws a rock and it goes up into the air and then falls back past him and lands on the ground below. The path of the rock can be modeled by the equation y=-0.02x^2 + 0.8x+37  where x is the horizontal distance in the meters from the starting point on the top of the hill and y is the heigth in meters, of the rock above the ground. How far horizontally from its starting point will the rock land? Round your answer to the nearest hundredth?

*37.00m
*67.43m
*27.43m
*37.78m

campbell_st · Answer

well I always start by drawing a graph...

campbell_st · Answer

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what do you know about the vertical height of the rock when it hits the ground?