Question

A ball is hurled in the air such that its horizontal (x) and vertical (y) shifts are given by the functions x(t) = 20t and y(t) = 40t − 5t2, where x and y are in meters and the time t is in seconds. What is the ratio of y to x at time t = 5 seconds?

Answer 1

0.25

0.50

0.75

0.85

Answer 2

@freckles

Answer 3

\[\frac{y}{x}\]
evaluate this at t=5

Answer 4

40(5)-5(5)^2/20(5)

Answer 5

\[\frac{40(5)-5(5)^2}{20 \cdot 5}\]
yes evaluate that :)

Answer 6

0.75?

Answer 7

you know what math im doing?

Answer 8

@freckles